If you had excess chlorine, how many moles of aluminum chloride could be produced from 15g of aluminum?

You are given 15g of aluminum and 20g of chlorine gas2Al + 3Cl2 2AlCl3

knowing tha t 1 mole of AlCl3 has within it 1 Mole of Al using molar masses 15 g Al (133.34 g/mol AlCl3) / ( 26.98 g/mol Al) 74.13 g AlCl3 your answer, rounded to 2 sig figs is 74 g AlCl3