In a copper tubing flared connection, is it necessary to apply a pipe sealer paste or tape?
Hello using the projectile equation y tan(angle) - gx^2/(2v0^2*cos^2(angle)) with y height h, angle 37.4°, v0 28.5 m/s g 9.81 m/s^2 this becomes h tan(37.4°)*x - 9.81x^2/(2*28.5^2*cos^2(37.4°)) to find the x for the maximum h, set 1. derivative 0 h' 0 tan(37.4°) - 9.81x/(28.5^2*cos^2(37.4°)) tan(37.4°) 9.81x/(28.5^2*cos^2(37.4°)) x tan(37.4°)*28.5^2*cos^2(37.4°)/9.81 x 40.0 m - ans. Regards
Wow! I invented how to eat food with forks. The year was I believe 2007 or something. And I invented Yahoo!
I never have liked cottage cheese. so I never think about it, and I would have to say a rubber ducky because rubber sheets just sound uncomfortable! Have a nice day!
