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Question:

LMTD of heat exchange?

In a heat exchanger the inlet and exit temperatures for the cold fluid are 20 C and 55 C respectively; and these temperatures for the hot fluid are 90 C and 65 C. The correction factor of the heat exchanger (F) at this operating condition has been calculated to be 0.85. Which one is the correct answer for the LMTD of this heat exchanger?Answer A.26.2 °C B.33.8 °C C.36.3 °C D.30.8 °C

Answer:

LMTD = F * [{(Tin - tin) - (Tout - tout)} / ln {(Tin - tin)/(Tout - tout)} LMTD = 0.85* [{(90-20) - (65-55)} / ln {(90-20)/(65-55)} = 26.2

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