A certain solenoidal inductor has a magnetic flux of 835 μWb through each loop of its coil when the current flowing through it equals 0.600 A. If the solenoid has 125 loops, what is its inductance (H)?
Magnetic flux Φ is calculated by Magnetic Circuits Ohms Law Φ F_M/R_M N I /R_M where Φ is magnetic flux in Webers (Wb). F_M is magneto-motive force in Ampere-Turns (A?T). F_M N I N is number of turns on solenoid in turns (T). I is current in solenoid in Amps (A) R_M is reluctance in A?T/Wb. Solve for reluctance. R_M N I /Φ 125 turns * 0.600 A/ 835 μWb 75A?T/ 835 μWb 89820 A?T/Wb Inductance L N^2/R_M (125 turns)^2/89820 A?T/Wb 0.174H
