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Question:

Inductors in ac Circuits, help please?

Here is the question:Two ideal inductors (.10 H, .50 H) are connected in series to an ac voltage source with amplitude 5.0V and frequency 126 Hz.a) What are the peak voltages across each inductor?b) What is the peak current that flows in the circuit?I know that you use V IXL *L is subscript*.I don't know if you are supposed to use rms in the equation like Vrms Vpeak/1.4 (square root of 2).Any help would be greatly appreciated and showing me the work/equation you are using. I am just generally confused lt;. Thanks a lot.

Answer:

The question ask for peak voltages and peak current. So I don`t think you have to worry about RMS values especially since the source voltage was not specified to be peak or RMS. The voltage across the .1H coil .1H / ( .1H + .5H ) x 5V .83V The voltage across the .5H coil .5H / ( .1H + .5H ) x 5V 4.17V Assuming the 5 volt ac source is sinusoidal then X of L (2 PI) x (frequency) x (inductance). The total impedance 6.28 x 126 x .6 475 ohm The current Voltage / impedance The circuit current 5V / 475 ohm 10.5 miliamps
If the 'amplitude' is 5v, then that's the peak value. you gotta take the r.m.s value and solve that problem :-)

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