What is the amount of heat required in each of the following?kilojoules to heat 165 of copper from 24 to 190
Hi There, Well, you’re missing a few details – I think I can fill them in but you will have to check and make sure they’re right. I assume that your “165 of copper” means “165 *grams* of copper” and that the 24 and 190 are in degrees C. We also have to know one more thing – the heat capacity of copper. A quick Google tells us it’s 0.385 J/(g-C). This means that it takes 0.385 J to heat up 1 g of copper by 1 deg C. (Likewise, it means copper gives up 0.385 J per gram for each degree C it cools off). Works either way. SO, with that, we can use the equation Q = (m) x (Cp) x (Tf – Ti) Where m = mass of the object in grams Cp = heat capacity, J/(g-C) Tf = ending temperature in C Ti = starting temperature in C Just plug in the numbers: Q = (165 g) x (0.385 J/g-C) x (190 C – 24 C) Q = 10,500 J (rounded) = 10.5 kJ Does that help?
