A grain silo has the shape of a right circular cylinder surmounted by a hemisphere. If a silo is to be constructed to have a capacity of 2000 cubic feet, then what height and radius of the silo will require the least amount of construction material?So far all i have is 2000 = (4*pi*R^3)#92;6 + pi*R^2*Ythen i solve for Y and get (2000-(4piR^3#92;6))#92;piR^2 without simplifying of course, anyway when i substitute Y in the volume equation i get the only possibility is X = 1, but i was under the inpression there should be more than one possibilities because that would make for a 600 some foot tall silo, plus tells nothing of building material unless i compare the findings to the total areas of other combinations.The silos radius must be equal to the cylinders so im not sure.I cant figure out if i solved for Y right, so i do volume of spere + volume of cylinder, then solve for y, or just solve it with the cylinder formula, can someone just do this problem for me i give up.
buy a graphing calculator works for me all the time recommend a Ti89 or the advanced Ti91 they are great just plug ecerything in and presto! the answer in readable terms
