Multiplying out bracket?

Hi,The equation is as follows: f[50f(1-f)]N-FSolution is 50Nf^2 - 50Nf^3 - F but can't figure out how they got there.

Answer:

f[50f(1 – f)]N – F . . . . . - expand the innermost bracket by distributing 50f f[50f – 50f?]N – F . . . - distribute f [50f? – 50f?]N – F . . . - distribute N 50Nf? – 50Nf? – F Done

sorry - its waaaaaaay over my head. GOOD LUCK!!!!

f*[50*f(1-f)]*N-F 1st: Distribute the f over the the bracket and collect terms [f*50*f*(1-f)]*N-F 50*f^2*(1-f)*N - F 2nd: Distribute the 50*f^2 over the the parentheses and collect terms (50*f^2-50*f^2*f)*N - F (50*f^2-50*f^3)*N-F 3rd: Distribute the N over the the parentheses and collect terms 50*f^2*N-50*f^3*N-F 4th: Now regroup 50*N*f^2-50*N*f^3-F

f[50f(1-f)]N-F Start inside the square brackets: 50f(1-f)50f-50f^2 So you've got: f[50f-50f^2]N-F Then: [50f^2-50f^3]N-F Which multiplies out to: 50Nf^2 - 50Nf^3 - F