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Question:

Need help calculating the heat released per mole of electrons transferred?

This question is part of the lab, where it states its problem:What quantity of heat energy is released when aluminum foil reacts with a solution of copper (II) chloride?Evidence:mass of aluminum reacted 0.45 gvolume of solution 100.0 mLinitial temperature (of solution) 24.0 'Cfinal temperature (of solution) 46.5'CAssumptions:- no heat is lost to the surroundings- the solute occupies no volume- the soultion has same specific heat capacity as water.Thanks for your help.

Answer:

I enjoy colder temperate too but you do need to stay warmyour body is mostly made of water and water freezesSo will your body if you continue to stay out in the coldFor keeping warm, I absolutely hate BIG weighted coversI would kick them off because you get too hot with big coversJust put a little more clothes on and thy to remain a comfortable tempI used to wear a tank top, over shirt, shirt and a jacketThose were my layers.
delta H m C dT delta H water 100.0 grams (4.184 Joules/g C) (22.5 Celsius) delta H water + 9414 joules absorbed by the water delta H reaction -9414 joules released by the reaction - 2 Al 3 CuCl2 - 2 AlCl3 3 Cu ( with 6 moles of electrons transfered) 0.45 grams Al 1 mol Al / 27 grams 1.668e-2 moles Al 1.668e-2 mol Al 6 mol electrons / 2 mol Al 5.004 e-2 mol of electrons - -9414 joules released / 5.004 e-2 mol of electrons 1.881 e5 Joules / mol electron the grams of aluminum have only 2 sig figs, so I have to round this off to 1.9 e5 Joules / mole electron or 1.9 e2 kiloJoules / mole of electron (190 kJ's/mol)

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