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Question:

physics calc based, it is about center mass please i need help?

fire hose 3.8 cm in diameter is capable of spraying water at a velocity of 12 m/s. For a continuous horizontal flow of water, what horizontal force should a fireman exert on the hose to keep it stationary

Answer:

Key point: in one second the volume of water flowing through the big hose and the small hose will be the same. (The flow speeds are be different) The volume of water flowing through a hose with cross area of A in 1 second is volumev*A where Api*r^2 thus volumev*pi*r^2 (v is the speed of water) For the large hose the water volume in 1 sec is: volumev1*pi*r1^2 For the smaller hose, volumev2*pi*r2^2 equating the 2 equations, v1*pi*r1^2 v2*pi*r2^2 v2v1*(r1/r2)^2 v211*(6/2)^2 v299 m/s
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