Physics Problem 2 Wheels rolling without slipping?
Throw me for a loop. HA! You're killin' me. Wheel 1: ω ωo + αt 1rad/s + 0.3rev/s? * 2πrad/rev * 20s 38.7 rad/s after 20 s. ← (a) Then the linear speed of the belt is (equal to the tangential speed of the wheel, which is) v ωr 38.7rad/s * 2m 77.4 m/s ← (c) Θ Θo + ωo*t + ?αt? 0 + 1rad/s * 20s + ? * (0.3*2πrad/s) * (20s)? 397 rads ← (b) Given the linear speed of the belt, then wheel 2's angular speed is ω v / r 77.4m/s / 3m 258 rad/s ← (d) barring computational error. (EDIT: I misread the acceleration as 3rev/s? on first run-through.)
Kinetic power a million/2mv^2 (0.5 mass circumstances velocity squared) fifty 5 a million/2m(3.2^2) a hundred and ten 10.24m m 10.74kg Circumference of circle 2(pi)r (rradius in metres) 2(pi)(0.09) 0.565m If it travels 3.2metres in step with 2d then in 5 seconds it travels 16m So sixteen/0.565 28.3 revolutions
