A inductor L is in series with a resistor R50 ohms, and the series combination is across the 120 V rms, 60 Hz power line. If the rms voltage across the resistance R is 90 V, (I) what is the rms inductor current? (ii) Calculate the inductance L(i) VI (XL)---I90/50---I1.8 A(ii) (Vo)^2Vr^2+(VL-Vc)^2 is where I am confused. I asked my professor and he said use 2(pi)fL to helpI also calculated VL---120^290^2+VL^2. VL79.37 V rms
You ve calculated the RMS voltage of the inductor. Now you need to find the impedance of the inductor. XL ωL 2πfL Now the voltage equation for the inductor XL * i(RMS) V(RMS) 2πfL * i V L V / (2πfi) L 79.37 / (2 * π * 60 * 1.8) L ≈ 0.117 H 117 mH
