Ok, I‘ve been racking my brain trying to figure this problem out with no success. Does anyone know the answer? Here‘s the question:A hydraulic lift is used to raise a car weighing 17000 Newtons. The piston used to raise the car had a cross-sectional area 50 times that of the smaller piston of the lift. What is the size of the force that must be applied to the smaller piston in order to raise the car?
the axles connect to the transmission, so they could have been hurt, but most places will not do that. if your transmission needed replacing, it could mean that lots of things need replacing. I had a shop cut the seal on the ends of the drive shaft in my car, so that they would fail in 6 months. I had no evidence, and no legal case to get them replaced, I was going to confront them and see what I could get, then found out they had been arrested for fraud.
the axles connect to the transmission, so they could have been hurt, but most places will not do that. if your transmission needed replacing, it could mean that lots of things need replacing. I had a shop cut the seal on the ends of the drive shaft in my car, so that they would fail in 6 months. I had no evidence, and no legal case to get them replaced, I was going to confront them and see what I could get, then found out they had been arrested for fraud.
17000 / 50 in moving 50 mm the smaller piston displaces enough liquid to move the larger piston 1mm. This is a mechanical advantage of 50 (ignoring friction)
Both front axles? How many did the mechanic tell you the car has?
17000 / 50 in moving 50 mm the smaller piston displaces enough liquid to move the larger piston 1mm. This is a mechanical advantage of 50 (ignoring friction)
