the actual speed of a six pole a.c motor operating from a 50hz supply with a 6% slip is what?how do i work this out please
Synchronous Speed of an AC Motor (Ns) = 120 x f / P where 120 is a constant, f the frequency and P the number of poles. In your case, Ns = (120 x 50)/6 = 1000 RPM Slip is the difference between synchronous speed and actual speed. So 6 % slip means (6 / 100) x 1000 = 60 RPM So actual speed is 1000 - 60 = 940 RPM Good luck
n=120f/p =120(50)/6 =1000 slip speed=0.06(1000) = 60 Actual speed= 1000-60 =940 rpm
