The coefficient of static friction between the tires of a motorcycle and the road is ?s 0.46. At a speed of 13 m/s, what is the radius of the tightest unbanked turn that the driver can handle?answer in m.Cannot figure this dang question, please help.
where to START? i would say the starter button. usually located on handlebars
Amax g*Cf 9.8*.46 4.51 m/s? R V?/(Amax) 13?/4.51 37.49 m
The formula for centripetal force is F mv^2 / r The centripetal force here is .46 * m * g So .46 * g v^2 / r .46 * g 13^2 / r
I would take the time to do this but Steve hit the nail on the head! Good job Steve.
Amax g*Cf 9.8*.46 4.51 m/s? R V?/(Amax) 13?/4.51 37.49 m
The formula for centripetal force is F mv^2 / r The centripetal force here is .46 * m * g So .46 * g v^2 / r .46 * g 13^2 / r
I would take the time to do this but Steve hit the nail on the head! Good job Steve.
where to START? i would say the starter button. usually located on handlebars
