Note: I'm asking this question to verify my work -- not just to get the answer. A house painter uses the chair and pulley arrangement to lift himself up the side of a house. The painter's mass is 70 kg and the chair's mass is 10 kg. With what force must he pull down on the rope in order to accelerate upward at .2 ms^2?The pulley is fixed to an overhanging part of the house. One end of a rope which goes around the pulley is connected to a platform where the painter sits. The other end of the rope is not connected to anything but is used by the painter to pull himself up (he exerts downward force on the rope).Please provide an explanation of the answer.
Hello The net force to accelerate 80 kg at 0.2 m/s^2 is a*m = 0.2*80 = 16 N. But the weight force pulls into the opposite direction, so the force has also to compensate for the weight force. The force needed is the weight of (painter + chair) + 16 N = mg + 16 = 80*9.81+16 = 800.8 N Regards
parent is critical to choose such kind of questions. there are fairly various suggestions of posting the figures . via technique of the regulation of parallelogram of forces , R = ? (P? + Q? + 2PQ cos ?) the placement ? is the perspective between the two forces. right here ? = 35? + fifty 4? = 89? R= ? (40? + 30 ? + 2*40*30* cos 89?) = 50.40 2 N tan ? = Q sin ? / (P + Q cos ?) the placement ? is the perspective between R and P tan ? = 30 sin 89 / ( 40 + 30 cos 89) ? = 36.50 ? from 40 N thinking ?2 = fifty 4?, the resultant is fifty 4- 36.50 = 17.5? below the horizontal contained interior the parent. =========================
