Iron (III) chloride can be made from the reaction of iron with chlorine gas. How much iron, in grams, will be needed to react completely with 58.0 grams of chlorine gas
The reaction for the synthesis of Iron (III) chloride from iron and chlorine can be written as 2Fe + 3Cl2 → 2FeCl3 Molecular mass of Cl2 gas35.5×271 So, 71 g of Cl2 gas1 mole 58 g of Cl2 gas 58/71 mole0.816901408 mole From the balanced equation, it is seen that 2 moles of Fe are required to completely react with 3 moles of Cl2 Therefore, no. of moles of Fe required to completely react with 1 mole of Cl22/3 Hence, no. of moles of Fe required to ompletely react with 0.828571428 moles of Cl2 2/3 × 0.816901408 0.544600939 Molecular mass of Iron55.845 g/mol mass of 1 mole of Fe55.845 mass of 0.544600939 moles of Fe0.552380952 × 55.84530.41323944 g Thus, 30.41323944 g of iron is required to completely react with 58 g of Chlorine gas.
The reaction for the synthesis of Iron (III) chloride from iron and chlorine can be written as 2Fe + 3Cl2 → 2FeCl3 Molecular mass of Cl2 gas35.5×271 So, 71 g of Cl2 gas1 mole 58 g of Cl2 gas 58/71 mole0.816901408 mole From the balanced equation, it is seen that 2 moles of Fe are required to completely react with 3 moles of Cl2 Therefore, no. of moles of Fe required to completely react with 1 mole of Cl22/3 Hence, no. of moles of Fe required to ompletely react with 0.828571428 moles of Cl2 2/3 × 0.816901408 0.544600939 Molecular mass of Iron55.845 g/mol mass of 1 mole of Fe55.845 mass of 0.544600939 moles of Fe0.552380952 × 55.84530.41323944 g Thus, 30.41323944 g of iron is required to completely react with 58 g of Chlorine gas.
