Is there a way to calculate the axial force of angular contact ball bearings?
The ball bearing theory is not subjected to axial force, but it will be subjected to slight axial force in practical application because it has certain centering action and will return to its original position after the axial force disappearsThe size of the axial force to have contact with the actual working environment, stress condition of ball bearings after the axial force is equivalent to the contact angle becomes similar to the angular contact ball bearing, the axial force and clearance of bearing, the ditch radius have a great relationship.Especially the clearance, the greater the clearance, the steel ball in the axial position of the greater the scope of movement, that is, the greater the axial clearance, the axial force can also be greater, but the clearance can not be blindly large.In short, we can tell you that the axial force is much smaller than the radial force. As for how to calculate it, the contact angle can not be predicted, so there is no way to knowMore exciting questions, please click on the account login electromechanical Online - Baidu cooperation know platform
The rated axial dynamic load of the bearing is: 4300N. Axial force can be calculated by formula. Please consult the professional manual!
This is the first response to the landlord, you can count, here introduces the concept of equivalent static load, a static equivalent radial load P0a (subscript 0A), a static equivalent axial load P0a (subscript 0A), and a static safety factor FS, we first check the static C0 7202AC (0 Department of AC, should represent the subscript) is the contact angle is 25 degrees, SKF C0 4800N, personally think that this value is too conservative, according to P0a=2.3*Fr*tg25+Fa (Fr is bearing radial load, axial load bearing is Fa, tg25 is the tangent, contact angle of 25 degrees according to the contact angle vary) and FS (fs=C0/P0) is greater than 1.5, launched: P0a less than 3200N, 1.07Fr+Fa less than 3200N that is to say, add up to force multiplied by the coefficient two component bearings, can not exceed this number. If only the axial force, the axial force is Fr=0, maximum 3200N can finally add a few points, FS safety coefficient is adjusted according to the condition, some places may be less than 1, and the place that cannot be less than 1.5, not less than 3, do not understand, temporarily by not less than 1.5. Also hope to help add master. And then there's the C0. Every brand might have a small difference. Here's SKF. So, if you calculate it in theory, you're going to make it smaller
