A science-fair radio uses a homemade capacitor made of two 55cm x 55cm sheets of aluminum foil separated by a 0.30-mm-thick sheet of paperAssume dielectric constant of paper is 3.0.What is the capacitance?Please show the steps you used in solving this problemIt will be very helpfulThanks
No, it's not 80%I can tell that from just reading the questionPercent yield actual yield/theoretical yield x 100Actual yield is experimental, in this case 0.571g H (0.571mol, since H is 1g/mol)Theoretical yield is the yield in mols from the balanced stoichiometryAccording to your equation, 2Al + 3H2SO4 - Al2(SO4)3 + 3H2 theoretical yield of H is 3 mols (3g) The in front of any molecule in a stoichiometry equation is of mols made/needed in a balanced reactionTherefore, percent yield is: 0.571mol/3mol 0.1903, x 100 19.03% yieldHow you got 80, I have no ideaBut it's very very wrongSorryHope this helps for future calculations! :)
hae,the equation is cvaccum permittyvity dielectric constantsarea/(distance) here Eo is 8.85410^-12farad/meter so you should change all in meter area55553025sqcm0.3025sqmeter distance between metal plates is 0.30mm0.3010^-3 c26.78nF(nano farad)
