A hydraulic jack is used to lift a 2800 pound car. If the output piston (the one the car is sitting on) has an area of 80 square inches, how much force must be applied to the 0.5 square inch input piston to lift the car?
5600 pounds because 2800/0.5 5600
The force multiplication is equal to the ratio of the areas, or 80/0.5 160 So the force is reduced by that amount, or 2800/160 17.5 pounds. .
