An electric oscillator is made with a 0.10 uF capacitor and a 1.0 mH inductor. The capacitor is initially charged to 5.0 V.
This may be an overly long method and an incorrect interpretation of the question but assuming it is an inductor and capacitor in parallel: Impedance of inductor 2πfL and imp. of capacitor 1 / (2πfC) When the current resonates the impedances are equal and thus this equation is formed: 1 / (2π√(RC)) f, the resonant frequency. So you calculate the frequency and that allows you to get the impedance of the inductor or capacitor - which turns out to be 100 ohms. In parallel two 100 ohm components give an impedance of 50 ohms (1 / R 1 / R1 + 1 / R2). Therefore the maximum current should be 5V / 50? 0.1 A
