When a small AC motor is operating at rated load from 115V, 60 cycle source, it takes 287 watts at a lagging power factor of 0.6. A. Calculate line current B. What should be the capacitance of the capacitor connected in parallel with the motor that will make the power factor unity? C. Determine the line current under this condition.
A. Power (287W) = V(115) x I x Cos phi (.6) I (amps) = P divided by V x cos phi = 287 / 115x.6 = 4.16 amps B. I will post later C. when you improve the power factor to 1 I (amps) = P divided by V x cos phi = 287 / 115x1 = 2.49 amps
