I know the resonant frequency is 1/sqrt(LC) and quality factor (1/r)(sqrt(L/C)) and I can use these to calculate my component values with a given resonant frequency, but every inductor has a resistance. How do I account for that in my design?Thank you in advance!
Using thick wire and ferrite core to make inductor that eliminate internal resistance as small as possible. The wire resistance could be as small as 0.5 ohm that would not affect too much to you design. If not, add its resistance to your calculation.
The resistance is the d.c. resistance of the inductor and could be measured, assuming that you have an inductor in front of you. If this is theoretical, it would be difficult because a particular inductance can be obtained with different coil configurations, winding conductor sizes, coil diameters, etc., that could not be directly related to a specific coil resistance. If you designed the inductor then you could use resistivity, diameter and length of conductor, otherwise it would just be a guess. In most cases, the inductor resistance is ignored, especially if the load resistance is high compared to the likely coil resistance.
Just insert a series resistor that is equal to the ESR of the inductor. If fr is large, you may also want to include the ESR of the cap.
