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Question:

Wrapped aluminum foil with 0.1mol metal sodium

With aluminum foil wrapped 0.1mol metal sodium in water by needle konza a plurality of small holes, after complete reaction, the volume of gas released (standard) (for)A. cannot determine that B.1.12L C. is greater than 1.12L and D. is less than 1.12L

Answer:

The formula is Na+Al+2H 2 O=NaAlO 2 +2H = 2, according to the equation of knowledge
Na reacts with water to produce NaOH and H 2, and NaOH and Al react to generate H 2 and NaAlO 2,
0.1molNa fully reacts to generate V (H 2), =2n (Na),.V, m, =2 * 0.1mol * 22.4L/mol=4.48L > 1.12L,So choose C.

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