A 105 kg scaffold is 6.2 m long. It is hanging with two wires, one from each end. A 520 kg box sits 2.2 m from the left end. What is the tension in the right hand side wire?(g = 9.8 m/s2)
assuming the 105 kg scaffold is uniform taking moment abt left end T * 6.2 = 105 *g * 3.1 + 520 g *2.2 T = 2322.76N answer tension in the right hand side wire
(105 x 9.8) = weight of 1,029N. Half is supported by each wire, = 514.5N. (520 x 9.8) = 5,096N. box weight. (6.2 - 2.2) = 4m. 5,096/((4//2.2)) +1) = 1,808.258N. (5,096 - 1,808.258) + 514.5 = 3,802.242N. tension in left wire.
