I found out that rising the frequency of the power going to the primary will rise the output/ secondary voltage. So, if I feed a 60 hz 1:1 turn ratio transformer 100volts at 60 Hz (pure sine wave), the output will be 100 volts. but if I increase the frequency to 400 hz and keep the primary voltage at 100V, (pure sine wave) the output/secondary voltage will go above 100 volts. Or no?
While transformers can be very efficient, they are not perfect, so for any significant load the voltage does not exactly follow the turns ratio. The losses will be different at varying frequencies, how they will differ is hard to predict without more information on the transformer. I'd imagine hysteresis losses might be noticeable, but that would probably cause core heating more than affect voltage much. Generally I'd expect little change in voltage especially at no load.
Because of the additional inductive reactance of the secondary winding at 400 Hz it seems reasonable to assume that the imaginary part of the load impedance at 400 Hz would be higher than at 60 Hz. This would result in an increase in the phase angle between circuit current and source Voltage but with a turns ration of one I think the secondary and primary Voltage both would be the same and equal to the source Voltage at either frequency.
this is yet in a diverse way. enable,Epvoltage around the popular winding; Es voltage around the secondary winding;Np # of turns interior the popular winding;Ns # of turns interior the secondary winding. Then, Ep (Es(Np))/N/s; (25(20))/one hundred500/one hundred 5V Step up transformer, or T turns ratio. T Ns / Np, one hundred/20 5v, Step up transformer. to your f.y.I in case you opt to parent a step down transformer,then, use the formula Es (Ep(Ns))/Np, or TNp/Ns desire this facilitates, persist with the electrical powered industry there's an incredible destiny and a few actual sturdy money to be made in it.
No. The voltage will not be different. The voltage ratio is proportional to turns ratio not frequency.ratio.
