A certain circuit consists of an inductor of 5 mH in series with a resistor of 200. At a moment when the current in the circuit is 19 A, a switch in the circuit is opened. How long will it take for the current to fall to 6.46 A? Answer in units of s.
First find the time constant: T L/R.005/200 take this answer and plug it in this equation; Second find time t: t T LN(Io/If) T LN(19/6.46). Don't answer in scientific notation.
