630 kilovolt transformer secondary side of the current is how much
There should be a second test voltage to calculate the current, but generally no load 400V. Full load 380V.
Primary side rated current: I = 630000 ÷ 10000 ÷ 1.732 = 36.37A
Secondary side rated current: I = 630000 ÷ 400 ÷ 1.732 = 909A
Maximum output power P = 630 * 0.95 = 599KW (COS ? by 0.95)
The maximum output power P = 630 * 0.9 = 567KW (COS ? by 0.9)
630kVA that his rated capacity, it is ideal to say that with the load of 630kW (but actually can not bring so much)
Rated current calculation formula: rated current = capacity / rated voltage / root number 3 (for 3-phase transformer)
630 / 0.4 / 1.732 = 909.3 A
Pure hand to play, hope to adopt ~
Secondary side rated current: I = 630000 ÷ 400 ÷ 1.732 = 909A
Primary side rated current: I = 630000 ÷ 10000 ÷ 1.732 = 36.37A
Maximum output power P = 630 * 0.95 = 599KW (COS ? by 0.95)
The maximum output power P = 630 * 0.9 = 567KW (COS ? by 0.9)
Transformer (Transformer) is the use of electromagnetic induction principle to change the AC voltage of the device, the main components are primary coil, secondary coil and core (core). The main functions are: voltage conversion, current conversion, impedance conversion, isolation, voltage regulator (magnetic saturation transformer) and so on. According to the purpose can be divided into: power transformers and special transformers (electric furnace change, rectifier, frequency test transformer, voltage regulator, mine transformer, audio transformers, IF transformers, high-frequency transformers, impact transformers, instrument transformers, electronic transformers , Reactors, transformers, etc.). The circuit symbol is commonly used as the beginning of the number.
