An electric hoist does 196,000 J of work in raising a 250.0 kg load. How high was the load lifted? answer in m
W=Fd F=ma ; a=g=9.8 m/s^2 m=250.0kg W=196000 J 196000 J=(250.0 kg)(9.8 m/s^2) * distance distance = 80 meters
196,000 ÷ (250 x 9.81) = 80 metres.
