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Question:

An inductor of 210 turns?

An inductor of 210 turns has a radius of 3 cmand a length of 16 cm.The permeability of free space is1.25664 x 10^-6 N/A^2.Find the energy stored in it when the cur-rent is 0.5 A. Answer in units of J.

Answer:

The stored energy is 1/2 L I^2 L (permeability) (turns)^2 (area) / length.
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