An iron ore sample is found to be 35.00% Fe by mass. How many grams of ore is needed to obtain 454.0 grams of Fe? pls help w/ step by step solution thx!!!
If you think about the 454 grams as 35% of the entire mass, it may make the problem easier. You can set up an equality, 454/35 x/100. Then cross multiply and solve for 'x' to get 1297.142g.
moles of SnCl2 moles of Sn2+ M*V 0.one million*22.4 2.24 millimoles Moles of Fe3+ 2*moles of Sn2+ 4.40 8 mmoles. Mass of Fe3+ 4.40 8*fifty six 249.seventy six mg % of Fe3+ 0.24976/0.745*a hundred% 33.fifty 3%
