Home > categories > Machinery & Equipment > Gantry Cranes > AP Chemistry Question help?
Question:

# AP Chemistry Question help?

I'm taking AP chem this upcoming year but am having a little trouble with my summer assignmentCould you tell me if I did this right or if not, show me how to? Thank you!Calculate the mass of 1.00ft^3 of gold metal.In my textbook it said the density of gold is 19.32g/cm^3So I converted the volume of 1.00ft^3 into cm^3.(1.00ft^3) (12in^3/ 1ft^3) (2.54cm^3 / 1in^3) 30.48 cm^3I then took the new volume and the given density and used the formula d m/vdm/v or m vd m (19.32g/cm^3) (30.48cm^3)m 588.87 g

## Answer:

First of all your cubic calculations are incorrect In 1 ft ( linear) there are 12 insIn 1 cu.ft there are 12in x 12 ins x 12 ins 1728 cu.ins However changing the pitch of conversionin 1in there are 2,54 cmthere in 12 in there are 12 x 2.54 30.48 cm But in 1 cuft there there 30.48 x 30.48 x 30.48 28316.85 cm^3 In 1 cm^3 there are 19.32 g of Gold So in 28316.85 cm^s x 19.32 547081,4762g 547081.4762 g 547.0814762 kg 547.0814762 0.547 tonnes So 1cu.ft of Gold has a mass of approximately half a metric tonneAs a very rough approximation this is 1/2 ton ( Imperial ton) You would NOT be able to lift it by hand ; too heavy!!! You would need a crane or fork lift truck.
First of all your cubic calculations are incorrect In 1 ft ( linear) there are 12 insIn 1 cu.ft there are 12in x 12 ins x 12 ins 1728 cu.ins However changing the pitch of conversionin 1in there are 2,54 cmthere in 12 in there are 12 x 2.54 30.48 cm But in 1 cuft there there 30.48 x 30.48 x 30.48 28316.85 cm^3 In 1 cm^3 there are 19.32 g of Gold So in 28316.85 cm^s x 19.32 547081,4762g 547081.4762 g 547.0814762 kg 547.0814762 0.547 tonnes So 1cu.ft of Gold has a mass of approximately half a metric tonneAs a very rough approximation this is 1/2 ton ( Imperial ton) You would NOT be able to lift it by hand ; too heavy!!! You would need a crane or fork lift truck.

Share to: