I am given the following circuit:
The time to starts with the inductor charged to 5 v and the 1K resistor sitting with 1Kv across it. When the switch is closed the inductor charges from 5 v to 1000 v in 5 time constants exponentially.
This is a simple RL circuit. The Thevenin equivalent of the current source is 1000 volts in series with 1k. (The 2.2k resistor in series with the current source has no effect, because the output resistance of the current source is infinite.) The initial current in the inductor is 5/100.05 amps. The final current is 1 amp. The inductor current changes exponentially between the initial value and the final value with a time constant of L/R. You should be able to determine the equation with the information I have given you.
