The piston of a hydraulic aut0mobile lift is .30m in diameter. What gauge pressure, in pascals, is required to lift a car with a mass of 800kg? Also express this pressure in atmospheres.
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800kg / pi {(1/2)(0.30m)}^2 Now convert the kg/m^2 to pascals.
Hydraulic Automobile Lift
w8 of the car is wm*g, and this w8 yields pressure Pw/A, where area Api*(0.3/2)^2; thus P800*9.8 / (pi*(0.3/2)^2) 110913 Pa ≈ 1.1 atm;
Hook them up to a flasher unit.
