Ship A sights Ship B on a bearing of 087°. Determine the bearing of A from B. Be sure to label your answer. Please show me the steps you went through to get the answer it will help me understand what you did to come to that. Thank you in advance
Draw yourself a picture of what is going on. Bearings are normally the angles from true North. Draw A with NSEW cross hatched Draw B with NSEW cross hatched. Then extend line from A to B and put in the 87 degree angle from N. Then add up the angles ---- 3 + 90 + 87 = 180 degrees from B to A. So B is 87 degrees E of N of A and A is 3 degrees S of W of B.
the trick with bearings is that a bearing angle is different from a mathematical angle. bearing angles are measured from due north and are positive clockwise. [so east is +90 and west is -90] mathematical angles are measured from due east and are positive counter-clockwise. [so east is 0 and north is +90.] so B is almost due east of A, just a little north of it. so A must be almost due west (-90) just a little south of B (-(90+)) draw the picture, use supplementary or opposite angles to find that A is at a bearing -93 deg = 360-93 = 267 deg from B
