A crane is being used to lift a container onto a cargo shipYou need to program the crane so that it lifts the container with a constant positive acceleration, a, during the first half of the lift and with a constant negative acceleration of the same magnitude, -a, during the second half of the liftYou want to do this so that the maximum speed of the crane is 1.5 m/sThe containers are initially at rest on the dock.The container has a mass of 1350 kg and the total distance the container is lifted is 4.5 m.What force must you have the crane lift the container during the first half (accelerating upwards) part of the lift?Give you answer in Newtons to four digits.
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For the lifting phase, the distance is 2.25 m the final velocity is 1.5 m/s the formula to use to find the acceleration is v^2 v0^2 + 2as 1.5^2 0^2 + 2a2.25 a 1.5^2/4.5 a 0.5 m/s^2 the necessary force is F m(g+a) F 1350(9.81 + 0.5) F 13918.5 N OG
