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Question:

Help with understanding this physics concept.?

Help with understanding this physics concept.?

Answer:

Well you see, the brick can't simply 'fall' once it loses contact with the other bricks because it is already moving UPWARDSWhat happens is that the brick keeps moving upwards with the initial speed of 5m/sIt can't just suddenly fall because the brick's inertia (resistance to changes in motion) carries it forwardThe brick reaches a maximum height above the position where it was when it initially lost contact, and then dropsSo to find the maximum height it can reach, simply apply the equations of motions as you've probably done many times before: The one you need is v^2 - u^2 2as u 5 m/s v 0 m/s (at the maximum, the brick will stop moving) a -9.8 m/s^2 (DON'T forget the minus sign) t don't care s what we want to know So just rearrange for sThis then tells us the extra height the brick travels after it loses contactI calculated it to be 1.28m So now, to get the maximum height above ground, you simply add 6 m (the height above ground) to thisSo the final answer is 7.28mI hope this helps!
Well you see, the brick can't simply 'fall' once it loses contact with the other bricks because it is already moving UPWARDSWhat happens is that the brick keeps moving upwards with the initial speed of 5m/sIt can't just suddenly fall because the brick's inertia (resistance to changes in motion) carries it forwardThe brick reaches a maximum height above the position where it was when it initially lost contact, and then dropsSo to find the maximum height it can reach, simply apply the equations of motions as you've probably done many times before: The one you need is v^2 - u^2 2as u 5 m/s v 0 m/s (at the maximum, the brick will stop moving) a -9.8 m/s^2 (DON'T forget the minus sign) t don't care s what we want to know So just rearrange for sThis then tells us the extra height the brick travels after it loses contactI calculated it to be 1.28m So now, to get the maximum height above ground, you simply add 6 m (the height above ground) to thisSo the final answer is 7.28mI hope this helps!

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