How many minutes will it take a current of 37.779 Ampères to deposit 46.053 grams of aluminum (26.981538 g/mol)CAN ANYONE HELP ME PLZ!
skip your lunch, and eat only salad in the lunch time ( raw green vegetables)but never skip breakfast and dinnerafter breakfast and dinner dink apple cidar vinegar one teaspoon diluted in half cup of waterit will help in weight loss without any side effects.
there are 3500 calories in a pound of fat, you have to burn more calories than u take in dailyswimming burns the most calories, also stay busykeep moving,the more you move the more calories burned, jump up and down, dance, pace, do chores, cook dinner, (light calorie meals) and no beverages other than waterwater keeps your skin clear and helps the body flush out fatsoda, alcohol empty caloriesand dont starve or your metabolism will slow down and make it hard to burn what little calories u take inthen when u get tired of starving and have a meal your metabolism will still burn the calories slowlyeat about 1200 calories a day and move around a lotdont stop moving!
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The electrical current (in amperes, amps) is the rate of flow of charge1 amp 1 coulomb/secAnother important value is the charge on a mole of electronsThat is the Faraday, or 96,500 coulombs / molThe last piece of the puzzle is the number of electrons needed to deposit an atom of aluminumThat would be threeAlso, we can say that a 3 moles of electrons will deposit 1 mole of aluminumA few conversion factors later and we'll have the time needed to deposit 46.053 grams 46.053 g Al x (1 mol Al / 26.9815 g Al) x (3 mole e- / mol Al) x (96,500 coulombs / mol e-) x (1 second / 37.779 coulombs) x (1 minute / 60 seconds) 217.99 minutes
