OK I have 500g of Zinc Sulfate heptahydrate, now how much would I need to turn a 0.2528 lb copper chunk silver?
moles copper = 114.66 g ( 1 mol / 63.546 g) = 1.804 the balanced equation is ZnSO4 * 7 H2O + Cu = CuSO4 + Zn + 7 H2O the ratio between copper and zinc sulphate heptahydrate is 1 : 1 moles zinc sulphate heptahydrate = 1.804 molar mass ZnSO4 = 161.47 g/mol molar mass ZnSO4 * 7 H2O = 161.47 + ( 7 x 18.02 )=287.61 g/mol mass ZnSO4 * 7 H2O required = 1.804 mol x 287.61 g/mol=518.85 g
it incredibly is a displacement reaction. As according to the reaction ZnSO4 and Cu would be formed. ZnSO4 would be in answer and has colourless. Copper which would be triggered, having dark brown in color. yet below widespread undertaking finished of CuSO4 heavily isn't decreased. It potential ultimately you will get CuSO4(aq) ZnSO4(aq) and Cu(s) in beaker. in case you shop the answer for a while, Cu would be settled down and color of the answer would be easy blue. On stirring the answer, it will be dark brown by way of Cu. even although, if CuSO4 is punctiliously decreased then ZnSO4 would be in answer (colourless) and dark browm Cu would be settled down.
