An inductor (L 400 mH), a capacitor (C 4.43 ?F), and a resistor (R 500 ) are connected in series. A 48.0 Hz AC generator connected in series to these elements produces a maximum current of 290 mA in the circuit. What is the required maximum voltage?
circuit impedance Z R + j w L - j / (w C) where w is the angular frequency (rads/sec). The voltage is then given by V Z I (R + j w L - j / (w C)) I I assume that what you are given is the maximum amplitude of the current and what you want is the resulting voltage amplitude of the entire circuit. That is |V| |(R + j w L - j / (w C))| I So, just find the amplitude of the impedance and multiplied by the given current and you are done.
