A hydraulic machine that can raise a car weighing 50,000 N and rests on a piston with a cross-sectional area of 2m^2, what force must be applied to the smaller piston that has an area of 0.5m2, in order to lift the car? I don‘t understand how to do this problem, please explain.
Do you have the nut off were the arm is on the splines?It is splined and hard to get them off,you may need to pry it off as they are tight to the splines.
Hello Waywardperson2, pressure applied f/0.5 f is to be found out. This pressure with area 2 m^2 would give a force which balances 50000 N So f/0.5 * 2 50000 Hence f 50000 * 0.5 / 2 12500 N
