Hello men, I need some help on this one. Please show me how it's done.A 0.541 H inductor is connected in series with a ?uorescent lamp to limit the current drawn by the lamp. If the combination is connected to a 47.4 Hz, 74.4 V line, and if the voltage across the lamp is to be 55.4 V, what is the current in the circuit? (The lamp is a pure resistive load.) Answer in units of A.
The reactance of the inductor at that frequency is Inductive Reactance X? 2πfL 161 ohms Impedance Z √(R? + X?) where X X? – Xc The voltage across the resistor is orthagonal to the voltage across the inductor. so 74.4 √(55.4? + VL?) where VL is voltage across inductor. 5535 3069 + VL? VL 50 volts / 161 ohms 0.308 amps, which flows through both inductor and lamp. .
