A hoist exerts an upward force of 500N on an object with a mass of 50Kg. If the hoist started from rest, determine the power it expended to lift the object vertically for 10s, under these conditions.
Force = mass * acceleration 500 = 50 * acceleration acceleration = 10 metres per second squared distance = (initial velocity*time) + (0.5*acceleration*time^2) distance = 0 + 0.5*10*100 distance = 500 metres Power = Force * Distance / Time Power = 500 * 500 / 10 Power = 500 * 50 Power = 25000 W
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P = Fd/t d = at^2 = Ft^2/m = (500N*100s^2)/50Kg = 1km P = (500N*1Km)/10s = 50kW
