1. the ideal leverage.2. the force to lift a load of 1500N3. the real leverage if the real force is 620N4. the effectiveness of the system
radius, R 10 cm axle-radius, r 5 cm W 900 N Force, F 900 x 5 / 10 450 N ANSWER
The wheel radius is 700mm., the axle radius 200mm. Now just consider that a simple class 1 lever. The load is 700mm. from the pivot, the effort is only 200mm. from the pivot. So the mechanical advantage is 700/200, or 3.5:1. But as the effort distance is less than the load distance, that is negative 3.5:1. The above is assuming the axle is turning the wheel, and not the wheel turning the axle. If the latter, the MA will be positive 3.5:1. As there is no indication in your question as to where the quoted forces are applied, I will end here. You should be able to work it knowing the MA and whether neg or pos.
