the cable of Crane I creates and angle of 30 degree angle from the horizontal and the cable of Crane II creates an angle of 45 degrees from the horizontal.-draw a figure that gives a visual representation of the problem-write a vector to represent the tension on the cable of Crane I-write a vector to represent the tension on the cable of Crane II-write a vector to represent the 20000 lb cargo container being lifted -calculate the tension on both cables. Justify your answer.....please help me!!! thank you!!!!:)
I find this question very interesting, i'll keep here waiting for the answer.
All I can say is.. Big crane make big thing go up.
So I can't tell whether the cargo container is one ton (2000 lbs.) or ten tons (20,000 lbs.). For doing the problem, I'm using 2000 lbs., so you might have to multiply the answers by 10. Also, I'll use A and B for the cranes instead of I and II. (Vertical): A sin 30° + B sin 45° = 2000 == A + √2 B = 4000 (Horizontal): -A cos 30° + B cos 45° = 0 == -√3 A + √2 B = 0 Solve those equations simultaneously to get A = 4000/(1+√3) = 1464 lbs. and B = √(3/2) A = 1793 lbs. (Answers) The vectors are: A = 1464 (-i cos 30° + j sin 30° = -1268i + 732j (Answer) B = 1793 (i cos 45°i + j sin 45°) = 1268i + 1268j (Answer)
