water at a rate of 600 lm/hr runs through a heat exchanger, entering as saturated liquid at 30 psia and leaving as saturated vapor at 30 psia. the heat is supplied by a carnot heat pump operating from low temperature reservoir at 60 F. find the rate of work into the heat pump.
You are an engineer so you should try and figure it out from your book and examples from the text. But to lead you in the direction of the right answer: Look at the state of the water before it enters the HE, it is saturated liquid, which means that all the states are constrained (there is a temperature, pressure, U, H, V) that you know from the steam tables all about state 1. Now look at the state of the water after it enters the HE, it is saturated vapor, which means that it is constrained again ( you know the temp, press, etc from the steam tables). You can use your equations that you learned in class and information now to find the W of the heat pump.
For Water at 30 psia Hl = 218.82 BTU/Lb For Water Vapor at 30 psia Hv = 1164.1 BTU/Lb The Heat supplied by the carnot heat pump must= (1164.1-218.2)BTU/Lb x 600Lb/Hr = 567,540 BTU/Hr = the heat required by the exchanger. The work required into the heat pump = (I'll leave this up to you)
i'm fairly into underground and that i could desire to declare, that became especially respectable. You pause slightly between words and it could be greater suitable if the beats do no longer in basic terms repeat repeat repeat to the song, blend it up a splash. ultimately, you are able to evaluate getting some greater human beings at the same time to make the vocals a splash greater dynamic.
