parts name assembly drawing
a2^23 (2 raise to the power of 23) b2^0+2^1+2^2.+2^64 try solving it hehe dont have time
One grain on the first square 2^0 Two grains on the second square 2^1 Four grains on the third square 2^2 Grains on the 24th square 2^23 You can see that the total wheat at any point is one less than the amount that would be placed on the next square(The total placed on the first three square is 7 grains, and 8 grains would be placed on the fourth square.) the total on 64 squares is thus one less than what would be placed on a 65th square, or 2^64 - 1.
S, sum of a geometric series S a(1 - r^n) / (1 - r) where a first term n number of terms r common ratio between successive terms S 1 + 2 + 4 + 8 + + 2^63; There are n 64 terms S 1(1 - 2^64) / (1 - 2) S (1 - 2^64) / (-1) S 2^64 - 1 Answer: 2^64 - 1 grains of wheat is required to fill all 64 squares by the method described in the problem.
