What is the net torque about the axle?
there are four forces acting on the axle; each force generates a torque whose magnitude is F r sin(theta), where F is the force, and r sin(theta) is the perpendicular distance between the line of force and the rotation axis the 30N force at the top of the disk exerts a torque of 30N*0.22m in the clockwise sense the other 30N force exerts a torque of 30*0.05sin45 in the counterclocwise sense the 20N force acting straight down generates a torque of 20N*0.05m counterclockwise and the final force exerts no torque since the line of force goes through the axle the total torque is then 30*0.22-30*0.05sin45-20*0.05 in units of Nm
Great answer, but on the 30N force at the top of the disk actually exerts a torque of 30N*0.11m. 0.22m is the distance of the diameter, not the radius.
I'm sorry. I would help you, but I have no idea watt you're torquing about.
