They are air tight, they don't short circuit, and they're fully insulatedthey hold 0.05v at maxwhat could be wrong?
What do you mean by attenuation coefficient? is it this? The linear attenuation coefficient, also called the narrow beam attenuation coefficient, is a quantity which describes the extent to which the intensity of energy beam is reduced as it passes through a specific materialThis might be electromagnetic radiation beam or sound beamIt is used in the context of X-rays or Gamma rays, where it is represented using the symbol μ, and measured in cm-1It is also used for modeling solar and infrared radiative transfer in the atmosphere, albeit usually denoted with another symbol (given the standard use of μ cos(θ) for slant paths)In the case of ultrasound attenuation it is usually denoted as α and measured in dB/cm/MHzA small linear attenuation coefficient indicates that the material in question is relatively transparent, while a larger values indicate greater degrees of opacityThe linear attenuation coefficient is dependent upon the type of material and the energy of the radiationGenerally, the higher the energy of the incident photons and the less dense the material in question, the lower the corresponding linear attenuation coefficient will be.
Linear Attenuation Coefficient Of Lead
To answer with confidence I would need to at least see sketches of how you make them, the materials you use and your test set-up for charging and measuring themWithout that, I can only suggest that your method of charging them may be suspecte.g., if you put a voltage source across them and then turn off the voltage to see how much charge they hold, be sure your voltage source is not shorting them outI suggest you do the following: Measure the impedance of the capacitors with a digital multimeterTest the capacitors by tapping a battery across them in series with a resistorMeasure the process with a digital voltmeter or oscilloscope If they don't show a voltage equal to the battery when it is applied and/or if they don't show the same voltage when the battery is removed, there is some sort of leakage path.
