There is a circuit with a battery connected to two wires in parallel. Both wires are made of the same material and are of the same length, but the diameter of wire A is twice the diameter of wire B. Answer true or false for the following questionsThe curent through the battery is five times larger than the current through wire B.The power dissipated in wire A is 16 times the power dissipated in wire B.The voltage drop across wire B is larger than the voltage drop across wire A.The resistance of wire B is four times as large as the resistance of wire A.The resistance of wire B is twice as large as the resistance of wire A.
false false true flase false true -good luck
***EDIT - CORRECTION*** Thanks Bill (the other Bill) it helps to put numbers on it. ******************** If I understand your question: The curent through the battery is five times larger than the current through wire B. **TRUE** Because: Current A is four times current B. Total current = A+B, or 4+1=5 The power dissipated in wire A is 16 times the power dissipated in wire B. ***FALSE*** (EDIT - I was wrong the first time) Because: Power = VxA The voltage drop across wire B is larger than the voltage drop across wire A. **FALSE** Because: If two wires are parallel voltage is same at ends (Beginning point of A and B is the same poin, ending point of A and B is the same point). The resistance of wire B is four times as large as the resistance of wire A. **TRUE** Because: Resistance inversely proportional to square of wire diameter. The resistance of wire B is twice as large as the resistance of wire A. **FALSE** Because: Resistance inversely proportional to square of wire diameter. Also check out web site shown below. Let me know if this helps Bill
the diameter of wire A is twice the diameter of wire B This means the cross-sectional area of A is 4 times that of B, which means the resistance of A is 1/4 that of B. To put some numbers on it, if B is 4 ohms, A is 1 ohm, total R is 0.8 ohms. Which means that if you have 1 amp of current flowing, you have 0.8 volts drop across the two wires, and 0.8 amps flowing through A and 0.2 amps flowing through B. Power in A is 0.8*0.8 = 0.64W, power in B is 0.8*0.2 = 0.16W, total power is 0.8*1 = 0.8 watts 1. true, see above 2. false, 4 times 3. false, they have the same voltage drop, they are in parallel 4. true 5. false, see #4 .
